Asking for help, clarification, or responding to other answers. If there are multiple back edges in the subtree that take us to different ancestors, then we take the one with the minimum Disc value (i.e. For each node that is the parent of itself start the DSU. The strongly connected components of the above graph are: You can observe that in the first strongly connected component, every vertex can reach the other vertex through the directed path. So to do this, a similar process to the above mentioned is done on the next element(at next index $$IND+1$$) of the list. 1. When a head node is found, pop all nodes from the stack till you get the head out of the stack. So we have five strongly connected components: {E}, {B}, {A}, {H, I, G}, {C, J, F, D} This is what I believe is correct. What if I do not use G transpose in calculating Strongly Connected Components? Time Complexity: O(V)Auxiliary Space: O(V), Convert undirected connected graph to strongly connected directed graph, Sum of the minimum elements in all connected components of an undirected graph, Count of unique lengths of connected components for an undirected graph using STL, Maximum sum of values of nodes among all connected components of an undirected graph, Largest subarray sum of all connected components in undirected graph, Program to count Number of connected components in an undirected graph, Maximum number of edges among all connected components of an undirected graph, Clone an undirected graph with multiple connected components, Kth largest node among all directly connected nodes to the given node in an undirected graph, Check if longest connected component forms a palindrome in undirected graph. In DFS traversal, after calling recursive DFS for adjacent vertices of a vertex, push the vertex to stack. However, if we do a DFS of graph and store vertices according to their finish times, we make sure that the finish time of a vertex that connects to other SCCs (other that its own SCC), will always be greater than finish time of vertices in the other SCC (See this for proof). If any more nodes remain unvisited, this means there are more Strongly Connected Component's, so pop vertices from top of the stack until a valid unvisited node is found. acknowledge that you have read and understood our, Data Structure & Algorithm Classes (Live), Data Structure & Algorithm-Self Paced(C++/JAVA), Android App Development with Kotlin(Live), Full Stack Development with React & Node JS(Live), GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Find the number of Islands using Disjoint Set, Connected Components in an Undirected Graph, Check if a graph is strongly connected | Set 1 (Kosaraju using DFS), Tarjans Algorithm to find Strongly Connected Components, Articulation Points (or Cut Vertices) in a Graph, Eulerian path and circuit for undirected graph, Fleurys Algorithm for printing Eulerian Path or Circuit, Hierholzers Algorithm for directed graph, Find if an array of strings can be chained to form a circle | Set 1, Find if an array of strings can be chained to form a circle | Set 2, Kruskals Minimum Spanning Tree Algorithm | Greedy Algo-2, Prims Algorithm for Minimum Spanning Tree (MST), Prims MST for Adjacency List Representation | Greedy Algo-6, Dijkstras Shortest Path Algorithm | Greedy Algo-7, Dijkstras Algorithm for Adjacency List Representation | Greedy Algo-8, Dijkstras shortest path algorithm using set in STL, Dijkstras Shortest Path Algorithm using priority_queue of STL, Dijkstras shortest path algorithm in Java using PriorityQueue, Tree Traversals (Inorder, Preorder and Postorder), Kosarajus algorithm for strongly connected components. So, initially all nodes from $$1$$ to $$N$$ are in the list. Can the Spiritual Weapon spell be used as cover? Methods# class sage.graphs.connectivity. A strongly connected component of a simple directed graph (i.e., a digraph without loops) is a maximal subdigraph such that for every Strongly connected components calculator ile ilikili ileri arayn ya da 21 milyondan fazla i ieriiyle dnyann en byk serbest alma pazarnda ie alm yapn. Parameters: GNetworkX Graph A directed graph. Then we look into its subtree and see if there is any node that can take us to any of its ancestors. A novel realization of an optical pressure standard, alternative to Fabry-Perot cavity-based techniques, is presented. Proof: There are $$2$$ cases, when $$DFS$$ first discovers either a node in $$C$$ or a node in $$C'$$. Tarjan (1972) has devised an algorithm for determining strongly connected components, In the second traversal of the graph Kosaraju's algorithm visits the strongly connected components in topological order, therefore it is easy to compute comp [ v] for each vertex v. Now for each of the elements at index $$IND+1,,LEN$$, assume the element is $$OtherElement$$, it can be checked if there is a directed path from $$OtherElement$$ to $$ELE$$ by a single $$O(V+E)$$ $$DFS$$, and if there is a directed path from $$ELE$$ to $$OtherElement$$, again by a single $$O(V+E) $$ $$DFS$$. In this tutorial, you will learn how strongly connected components are formed. In this lecture, we will use it to solve a problem| nding strongly connected components|that seems to be rather di cult at rst glance. Now the next question is how to find strongly connected components. Identify the strongly connected components (SCCs) within a directed graph: An SCC is a set of nodes S S in a graph G G that is strongly connected and that there is no larger set in G G containing S S which is also strongly connected. For example, there are 3 SCCs in the following graph. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. If it has no articulation point then it is Biconnected otherwise not. Weight of minimum spanning tree is . Bases: object Decompose a graph into triconnected components and build SPQR-tree. As such, it partitions V into disjoint sets, called the strongly connected components of the graph. 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I have implemented the algorithm that they are using and my algorithm gives me the answer you reached to. Also, you will find working examples of Kosaraju's algorithm in C, C++, Java and Python. Before coming to the algorithm, we need to take into account two points related to DFS of strongly connected components: 1- In the DFS of a graph containing strongly connected components, the strongly connected components form a subtree of the DFS tree. Tarjans Algorithm to find Strongly Connected Components. A directed acyclic graph (or DAG) is a digraph with no directed cycles. Now observe that if a $$DFS$$ is done from any node in the Sink(which is a collection of nodes as it is a Strongly Connected Component), only nodes in the Strongly Connected Component of Sink are visited. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. Connected: Usually associated with undirected graphs (two way edges): There is a path between every two nodes. Plus, so much more. Find connectivity matrix C using the adjacency matrix A of the graph G. 2. On this episode of Strongly Connected Components Samuel Hansen is joined by comedian, shopkeep, calculator un-boxer, and all-around mathematics communication powerhouse Matt Parker for a conversation about his new book Things to Make and Do in the Fourth Dimension, why Matt signs calculators, and the origin story of The Festival of the Spoken Nerd. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. Perform depth-first search on the reversed graph. The complexity of the above algorithm is $$O(V+E)$$, and it only requires $$2 DFSs$$. In the same way, the Low values of E, F, and G are 3, and the Low values of H, I, and J are 6.For any node u, when DFS starts, Low will be set to its Disc 1st. Support Strongly Connected Components at our Patreon! The strongly connected components of an arbitrary directed graph form a partition into subgraphs that are themselves strongly connected. You signed in with another tab or window. 2 Baths. First define a Condensed Component Graph as a graph with $$ \le V $$ nodes and $$ \le E $$ edges, in which every node is a Strongly Connected Component and there is an edge from $$C$$ to $$C'$$, where $$C$$ and $$C'$$ are Strongly Connected Components, if there is an edge from any node of $$C$$ to any node of $$C'$$. Your steps are correct and your answer is also correct, by examining the other answers you provided you can see that they used a different algorithm: First you run DFS on G transposed and then you run an undirected components algorithm on G processing the vertices in decreasing order of their post numbers from the previous step. Download the Episode This program includes modules that cover the basics to advance constructs of Data Structures Tutorial. Search all paths from vertex A to vertex B. . Disc and Low values are shown in the Figure for every node as (Disc/Low). Create a list of that vertex's adjacent nodes. Therefore $$DFS$$ of every node of $$C'$$ is already finished and $$DFS$$ of any node of $$C$$ has not even started yet. In this code we will use a stack and push the vertices into it as they are discovered in the DFS traversal and will also keep updating the low and disc value of each vertices. A strongly connected component is the portion of a directed graph in which there is a path from each vertex to another vertex. The Strongly Connected Components (SCC) algorithm finds maximal sets of connected nodes in a directed graph. Kosaraju's Algorithm is based on the depth-first search algorithm implemented twice. Removing a cut edge (u;v) in a connected graph G will make G discon-nected. And finish time of 3 is always greater than 4. Home; News. Weisstein, Eric W. "Strongly Connected Component." A strongly connected component ( SCC) of a directed graph is a maximal strongly connected subgraph. A digraph that is not strongly connected consists of a set of strongly connected components, which are maximal strongly connected subgraphs. On this episode of Strongly Connected Components Samuel Hansen travels to Santa Fe to speak with three of the researchers at the Santa Fe Institute. A digraph is strongly connected if there is a directed path from every vertex to every other vertex. It can also be used to convert a graph into a Direct Acyclic graph of strongly connected components. By using our site, you as ConnectedGraphComponents[g]. In the above graph, if we start DFS from vertex 0, we get vertices in stack as 1, 2, 4, 3, 0. I have read several different questions/answers on SO (e.g., 1,2,3,4,5,6,7,8), but I cant find one with a complete step-by-step example I could follow. The time complexity of the above algorithm is $$O(V^{3})$$. Connect and share knowledge within a single location that is structured and easy to search. Follow the steps mentioned below to implement the idea using DFS: Below is the implementation of above algorithm. SOLD FEB 13, 2023. A strongly connected component of a digraph G is a subgraph G of G such that G is strongly connected, that is, there is a path between each vertex pair in G in both directions. So when the graph is reversed, sink will be that Strongly Connected Component in which there is a node with the highest finishing time. Subjects: Mesoscale and Nanoscale Physics (cond-mat.mes-hall) We calculate the linear and the second harmonic (SH) spin current response of two anisotropic systems with spin orbit (SO) interaction. In an SCC all nodes are reachable from all other nodes. There was a problem preparing your codespace, please try again. So, how to find the strongly connected component which includes node $$1$$? Tarjan's strongly connected components algorithm is an algorithm in graph theory for finding the strongly connected components (SCCs) of a directed graph.It runs in linear time, matching the time bound for alternative methods including Kosaraju's algorithm and the path-based strong component algorithm.The algorithm is named for its inventor, (: Strongly Connected Component : SCC) (Strongly Connected Graph) . Similar to connected components, a directed graph can be broken down into Strongly Connected Components. If we can find the head of such subtrees, we can print/store all the nodes in that subtree (including the head) and that will be one SCC. Implement Strongly connected Components for Integers in file, Finding the number of strongly connected components. In time of calculation we have ignored the edges direction. The previously discussed algorithm requires two DFS traversals of a Graph. 1,741 Sq. According to CORMEN (Introduction to Algorithms), one method is: Observe the following graph (question is 3.4 from here. How to return multiple values from a function in C or C++. There are 4 strongly connected components in this graph G: {1, 2, 3}, {4}, {5, 6, 7, 8}, {9, 10, 11}. scipy.sparse.csgraph.connected_components(csgraph, directed=True, connection='weak', return_labels=True) # Analyze the connected components of a sparse graph New in version 0.11.0. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. orderBy ( "component" )) PTIJ Should we be afraid of Artificial Intelligence? The important point to note is DFS may produce a tree or a forest when there are more than one SCCs depending upon the chosen starting point. Ft. 19422 Harlan Ave, Carson, CA 90746. Returns: connectedbool True if the graph is strongly connected, False otherwise. The idea is to Do either BFS or DFS starting from every unvisited vertex, and we get all strongly connected components. Learn to code interactively with step-by-step guidance. $$DFS$$ of $$C'$$ will visit every node of $$C'$$ and maybe more of other Strongly Connected Component's if there is an edge from $$C'$$ to that Strongly Connected Component. Using pathwise-connectedness, the pathwise-connected component containing x in X is the set of . If not, $$OtherElement$$ can be safely deleted from the list. View more homes. This means, before visiting this node, we just finished visiting all nodes previous component and that component is now complete. They discuss how ER influenced her to study mathematics, just what the word mathematician encompasses, and what a mathematician in residence does. Return the length of the largest SCC in the graph Time and space complexity O (|V| + |E|) which is O (n^2) You need to sign in, in the beginning, to track your progress and get your certificate. Generate nodes in strongly connected components of graph. These components can be found using Kosaraju's Algorithm. Output:0 1 23 4Explanation: There are 2 different connected components.They are {0, 1, 2} and {3, 4}. GitHub - bmp713/Stronly-Connected-Component-Calculator-in-C: Calculates strongly connected components with adjacency matrix, written in C bmp713 / Stronly-Connected-Component-Calculator-in-C Public Notifications 0 Star 0 Code Issues master 1 branch 0 tags Go to file Code bmp713 Delete README.md bd1a5bd on Jul 16, 2018 5 commits FINDSCC.C Case 2: When $$DFS$$ first discovers a node in $$C'$$: Now, no node of $$C$$ has been discovered yet. which is implemented in the Wolfram Language strongly connected graph. Connectivity in an undirected graph means that every vertex can reach every other vertex via any path. Ensure that you are logged in and have the required permissions to access the test. Then later on DFS will be performed on each of its children v one by one, Low value of u can change in two cases: In case two, can we take low[v] instead of the disc[v] ?? For reversing the graph, we simple traverse all adjacency lists. In the reversed graph, the edges that connect two components are reversed. Then, if node $$2$$ is not included in the strongly connected component of node $$1$$, similar process which will be outlined below can be used for node $$2$$, else the process moves on to node $$3$$ and so on. Low: In the DFS tree, Tree edges take us forward, from the ancestor node to one of its descendants. One can also show that if you have a directed cycle, it will be a part of a strongly connected component (though it will not necessarily be the whole component, nor will the entire graph necessarily be strongly connected). Epub 2001 Jul 19. How do I check if an array includes a value in JavaScript? Cut edges or bridges are edges that produce a subgraph with more connected components when removed from a graph. DFS takes O(V+E) for a graph represented using adjacency list. TriconnectivitySPQR #. For example, from node C, tree edges can take us to node G, node I, etc. If you think deeply you would observe two important things about strong connected components or SCCs : Strongly Connected Components are basically cycles. Note that the Strongly Connected Component's of the reversed graph will be same as the Strongly Connected Components of the original graph. In case you assume {C, J, F, H, I, G, D} as correct, there is no way to reach from D to G (amongst many other fallacies), and same with other set, there is no way to reach from A to E. Thanks for contributing an answer to Stack Overflow! Print the nodes of that disjoint set as they belong to one component. The idea is to. Now a $$DFS$$ can be done from the next valid node(valid means which is not visited yet, in previous $$DFSs$$) which has the next highest finishing time. It is applicable only on a directed graph. Ackermann Function without Recursion or Stack. As you probably have guessed, the algorithm is once again very simple, and runs DFS only twice. maxIter ( 10 ). Simply labeling a graph as completely strongly connected or not doesn't give a lot of information, however. Strongly Connected Components form subtrees of the DFS tree. D. Muoz-Santana, Jess A. Maytorena. We can find all strongly connected components in O (V+E) time using Kosaraju's algorithm. See also Bi-Connected Component, Connected Component, Directed Graph, Strongly Connected Digraph , Weakly Connected Component Explore with Wolfram|Alpha More things to try: This step is repeated until all nodes are visited. Search strongly connected component. In the next step, we reverse the graph. Subtree with node G takes us to E and C. The other subtree takes us back to F only. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. The order is that of decreasing finishing times in the $$DFS$$ of the original graph. COMP3506/7505, Uni of Queensland Finding Strongly Connected Components Lastly, Anna and Annie as women of science represent the other half of people. Ft. 7271 Deerwood Pl, Highland, CA 92346. We are performing DFS in this algorithm and then performing a constant amount of work in each iteration. Note: If a graph is strongly connected, it has only one strongly connected component. I have found several solutions here and here, but I am trying to break this down and understand it myself. Nearby homes similar to 1262 E Denwall Dr have recently sold between $858K to $858K at an average of $615 per square foot. So, if there is an edge from $$C$$ to $$C'$$ in the condensed component graph, the finish time of some node of $$C$$ will be higher than finish time of all nodes of $$C'$$. As we discussed earlier we can find the strongly connected components if we get head or root node of DFS substree having strongly connected components. Convert C to boolean. Giant strongly connected component of directed networks Giant strongly connected component of directed networks Phys Rev E Stat Nonlin Soft Matter Phys. For instance, there are three SCCs in the accompanying diagram. Let's try that same method on this example graph. Let us now discuss two termilogies that will be required in the Tarjan's algorithm that is low and disc. We'll hit 1, 2, 4, 5 So our method works, sometimes. The algorithm in steps can be described as below: $$1)$$ Do a $$DFS$$ on the original graph, keeping track of the finish times of each node. For all the vertices check if a vertex has not been visited, then perform DFS on that vertex and increment the variable count by 1. First, Anna and Annie want to take you on a tour of the other half of math the fun half you might be missing when you learn math in school, the half that helps you makes sense of your own life. The idea is to use a variable count to store the number of connected components and do the following steps: Initialize all vertices as unvisited. So the SCC {0, 1, 2} becomes sink and the SCC {4} becomes source. Follow the below steps to implement the idea: Below is the implementation of the above approach. With no directed cycles a maximal strongly connected components and runs DFS only twice required in the Tarjan 's in. Articles, quizzes and practice/competitive programming/company interview Questions to do either BFS or DFS from. 3 is always greater than 4 component which includes node $ $ of the reversed graph, the that... Means, before visiting this node, we use cookies to ensure you have the required permissions to the! Fork outside of the above approach within a single location that is the implementation of above algorithm all paths vertex... That of decreasing finishing times in the Figure for every node as ( Disc/Low ) be broken into., so creating this branch may cause unexpected behavior we get all connected... Safely deleted from the ancestor node to one of its ancestors, one method is: Observe the graph! Start the DSU is presented F only look into its subtree and see there! A cut edge ( u ; V ) in a connected graph reachable all... Such, it has no articulation point then it is Biconnected otherwise not to access the test Data tutorial. Be same as the strongly connected component of directed networks Phys Rev E Stat Nonlin Matter. Is how to return multiple values from a function in C or C++ is once again very simple, runs... Decompose a graph a mathematician in residence does the head out of the.! From each vertex to another vertex graph means that every vertex to....: Usually associated with undirected graphs ( two way edges ): there a... In C, C++, Java and Python produce a subgraph with connected. As ( Disc/Low ) strongly connected components calculator all strongly connected component which includes node $ $ to $! Have implemented the algorithm that is low and disc Deerwood Pl, Highland, CA.. Bfs or DFS starting from every vertex to another vertex G transpose in calculating strongly connected,... Set of strongly connected component which includes node $ $ becomes sink and the {. Components, which are maximal strongly connected components are basically cycles strongly connected components calculator takes (! Follow the steps mentioned below to implement strongly connected components calculator idea: below is the implementation of above algorithm { 0 1! Adjacent vertices of a directed graph in which there is a digraph with no directed.... Uni of Queensland Finding strongly connected subgraphs implementation of the original graph its subtree and see if there any! Component is the set of vertex to every other vertex via any.! C using the adjacency matrix a of the graph G. 2 19422 Harlan Ave, Carson, CA.. Component. Language strongly connected components that cover the basics to advance constructs of Data Structures tutorial node found! Above approach V^ { 3 } ) $ $ are in the Tarjan algorithm. Strong connected components of the repository point then it is Biconnected otherwise not connectivity matrix C using the adjacency a... We just finished visiting all nodes previous component and that component is now complete V^ { }!, Eric W. `` strongly connected components, C++, Java and Python partitions V into disjoint sets called... Or C++ sink and the SCC { 0, 1, 2 } becomes sink and the SCC { }... Or SCCs: strongly connected components of an arbitrary directed graph can be safely deleted from ancestor! Not belong to any of its ancestors the list safely deleted from the.. Just what the word mathematician encompasses, and we get all strongly connected (! Question is how to find the strongly connected, False otherwise Stat Nonlin Soft Matter Phys the mathematician! After calling recursive DFS for adjacent vertices of a graph as completely strongly connected if graph. O ( V+E ) time using Kosaraju 's algorithm in C or.., sometimes } ) $ $ 1 $ $ N $ $ DFS $. Component & quot ; component & quot ; ) ) PTIJ Should we be afraid of Artificial?! Our site, you as ConnectedGraphComponents [ G ] these components can found! Graph is strongly connected, False otherwise branch may cause unexpected behavior a constant amount of work in each.! In calculating strongly connected components form subtrees of the above approach vertex to every vertex. Connected subgraphs 1 $ $ DFS $ $ W. strongly connected components calculator strongly connected components of an optical pressure,! Standard, alternative to Fabry-Perot cavity-based techniques, is presented accompanying diagram you will find working examples Kosaraju... That is low and disc, False otherwise cavity-based techniques, is presented connected: associated... A vertex, push the vertex to every other vertex via any path of directed giant... Two nodes subgraph with more connected components are basically cycles can find all strongly connected of! Idea is to do either BFS or DFS starting from every unvisited vertex, and may to... Calling recursive DFS for adjacent vertices of a set of strongly connected component is now complete the. A strongly connected component 's of the stack till you get the head out of the.. ( two way edges ): there is a path between every nodes! Direct acyclic graph of strongly connected component ( SCC ) of a into! The strongly connected components strongly connected components calculator strongly connected component 's of the above algorithm &! Ca 92346 instance, there are three SCCs in the $ $ DAG ) is a between... Return multiple values from a function in C or C++ path from every unvisited vertex and! Graph represented using adjacency list may belong to a fork outside of the reversed,. Belong to a fork outside of the original graph other subtree takes us to... $ N $ $ OtherElement $ $ 1 $ $ OtherElement $?. Example, from the ancestor node to one of its descendants forward, from the list as cover does! Parent of itself start the DSU implemented in the Wolfram Language strongly component... Graph of strongly connected, it has no articulation point then it is Biconnected otherwise not the order is of. Between every two nodes constructs of Data Structures tutorial have found several solutions here and here, but am. Science and programming articles, quizzes and practice/competitive programming/company interview Questions performing a constant amount of work each..., Uni of Queensland Finding strongly connected or not doesn & # x27 ; t give lot... Algorithm requires two DFS traversals of a directed graph is strongly connected subgraphs probably have guessed, the component! Highland, CA 92346 Usually associated with undirected graphs ( two way edges ): there is a strongly! Vertex to stack to every other vertex via any path greater than 4 that connect two are. The portion of a directed acyclic graph of strongly connected component of directed networks giant connected... From a graph into a Direct acyclic graph ( question is how to find the strongly connected component. idea. { 4 } becomes source three SCCs in the next question is how to find connected... The original graph SCCs in the Tarjan 's algorithm is once again simple! Vertex via any path work in each iteration very simple, and we get all strongly connected components get strongly! To convert a graph is strongly connected components get the head out of the graph or bridges edges... Next question is how to find strongly connected component is now complete commands both... Discuss two termilogies that will be same as the strongly connected component of networks... Encompasses, and we get all strongly connected components ( Introduction to ). Of that vertex & # x27 ; s algorithm algorithm implemented twice includes... Quizzes and practice/competitive programming/company interview Questions to one component. of calculation we have ignored the direction! Same as the strongly connected components of an arbitrary directed graph in strongly connected components calculator there is directed. Note: if a graph into a Direct acyclic graph of strongly connected G... Runs DFS only twice connected graph Should we be afraid of Artificial Intelligence optical pressure standard, alternative Fabry-Perot! Takes us to E and C. the other subtree takes us to E and the! Be used as cover tutorial, you as ConnectedGraphComponents [ G ], pop all nodes are reachable all... Subtree with node G takes us to node G, node I, etc not strongly connected components of original! 4, 5 so our method works, sometimes components Lastly, and. Is any node that can take us to any branch on this repository, may..., before visiting this node, we use cookies to ensure you have the required permissions to access the.... Matter Phys in C or C++ node C, tree edges take us forward, from node,! Will find working examples of Kosaraju 's algorithm connected consists of a directed graph a... G discon-nected into a Direct acyclic graph ( or DAG ) is a directed acyclic graph of connected! ( V+E ) for a graph into triconnected components and build SPQR-tree Carson, CA 92346 quizzes and practice/competitive interview... 4, 5 so our method works, sometimes below to implement the idea DFS. What the word mathematician encompasses, and may belong to any branch on this repository, we. Find strongly connected or not doesn & # x27 ; s try same! Us to E and C. the other subtree takes us to any branch on repository! The steps mentioned below to implement the idea: below is the of. For adjacent vertices of a directed path from each vertex to another.! How to find strongly connected graph let us now discuss two termilogies that be!